What is expand (2z(z^2+2z-8))/((z-1)(z+2)) ?

The solution to expand (2z(z^2+2z-8))/((z-1)(z+2)) is (2z^3+4z^2-16z)/(z^2+z-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2z(z^2+2z-8))/((z-1)(z+2))

expand

\frac{2 z ( z ^{2} + 2 z - 8 )}{( z - 1 ) ( z + 2 )}

\frac{2 z ^{3} + 4 z ^{2} - 16 z}{z ^{2} + z - 2}

Solution steps

\frac{2 z ( z ^{2} + 2 z - 8 )}{( z - 1 ) ( z + 2 )}

Expand

(z - 1) (z + 2) : z^{2} + z - 2

= \frac{2 z ( z ^{2} + 2 z - 8 )}{z ^{2} + z - 2}

Expand

2 z (z^{2} + 2 z - 8) : 2 z^{3} + 4 z^{2} - 16 z

= \frac{2 z ^{3} + 4 z ^{2} - 16 z}{z ^{2} + z - 2}

\frac{e ^{x}}{( 1 - e ^{x} ) ^{2} d x}

(8 x^{2} + 4 y) x^{2} + y^{2} = 1

\frac{h ( α - ρ )}{α}

3 w^{2} (2 w^{2})

\frac{( 3 + i ) ^{4}}{81}

What is expand (2z(z^2+2z-8))/((z-1)(z+2)) ?
The solution to expand (2z(z^2+2z-8))/((z-1)(z+2)) is (2z^3+4z^2-16z)/(z^2+z-2)