What is (e^{iax})/((z^2+b^2)^2) ?

The solution to (e^{iax})/((z^2+b^2)^2) is (cos(ax))/(b^4+z^4+2b^2z^2)+i(sin(ax))/(b^4+z^4+2b^2z^2)

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simplify (e^{iax})/((z^2+b^2)^2)

simplify

\frac{e ^{ia x}}{( z ^{2} + b ^{2} ) ^{2}}

\frac{cos ( a x )}{b ^{4} + z ^{4} + 2 b ^{2} z ^{2}} + i \frac{sin ( a x )}{b ^{4} + z ^{4} + 2 b ^{2} z ^{2}}

Solution steps

\frac{e ^{ia x}}{( z ^{2} + b ^{2} ) ^{2}}

e^{ia x} = cos (a x) + i sin (a x)

= \frac{cos ( a x ) + i sin ( a x )}{( z ^{2} + b ^{2} ) ^{2}}

Rewrite

\frac{cos ( a x ) + sin ( a x ) i}{( z ^{2} + b ^{2} ) ^{2}}

in standard complex form:

\frac{cos ( a x )}{z ^{4} + 2 b ^{2} z ^{2} + b ^{4}} + \frac{sin ( a x )}{z ^{4} + 2 b ^{2} z ^{2} + b ^{4}} i

= \frac{cos ( a x )}{z ^{4} + 2 b ^{2} z ^{2} + b ^{4}} + \frac{sin ( a x )}{z ^{4} + 2 b ^{2} z ^{2} + b ^{4}} i

(2 x + y = 6) \cdot (- 4)

x ((x - 0.5) (x - 1))

\frac{( - y ^{2} + 4 ) ^{2}}{2}

\frac{e ^{s} + s ^{2} + s}{s ( s ^{2} + s )}

\frac{y ( 3 x + 1 )}{x}

What is (e^{iax})/((z^2+b^2)^2) ?
The solution to (e^{iax})/((z^2+b^2)^2) is (cos(ax))/(b^4+z^4+2b^2z^2)+i(sin(ax))/(b^4+z^4+2b^2z^2)