What are the solutions to the equation (x+4)(2x-5)=0 ?

The solutions to the equation (x+4)(2x-5)=0 are x=-4,x= 5/2

Find the zeros of (x+4)(2x-5)=0

The zeros of (x+4)(2x-5)=0 are x=-4,x= 5/2

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(x + 4) (2 x - 5) = 0

x = - 4, x = \frac{5}{2}

Decimal Notation

x = - 4, x = 2.5

Solution steps

(x + 4) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 2 x - 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - 4, x = \frac{5}{2}

25 (x - 3) + 3 = 75

\frac{6}{x - 7} \geq 3

8.99 \cdot 1 0^{9} \cdot \frac{1 \cdot 1 0 ^{- 6}}{3.01}

x^{(2)} + 24 x + 21 = 0

8^{2} + 4^{3} \cdot 2^{2}

What are the solutions to the equation (x+4)(2x-5)=0 ?
The solutions to the equation (x+4)(2x-5)=0 are x=-4,x= 5/2
Find the zeros of (x+4)(2x-5)=0
The zeros of (x+4)(2x-5)=0 are x=-4,x= 5/2