What is expand (-2x^2+8)/((x^2+4)^2) ?

The solution to expand (-2x^2+8)/((x^2+4)^2) is (-2x^2+8)/(x^4+8x^2+16)

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expand (-2x^2+8)/((x^2+4)^2)

expand

\frac{- 2 x ^{2} + 8}{( x ^{2} + 4 ) ^{2}}

\frac{- 2 x ^{2} + 8}{x ^{4} + 8 x ^{2} + 16}

Solution steps

\frac{- 2 x ^{2} + 8}{( x ^{2} + 4 ) ^{2}}

(x^{2} + 4)^{2} = x^{4} + 8 x^{2} + 16

= \frac{- 2 x ^{2} + 8}{x ^{4} + 8 x ^{2} + 16}

\frac{i}{8} \cdot (cos (2 π x) + i sin (2 π x))^{3}

\frac{( n + 1 ) ( n + 3 ) ( 2 n + 9 )}{6}

\frac{4 x ^{2}}{( 2 x ^{3} - 11 ) ^{\frac{1}{3}} \cdot ( 2 x - 1 )}

\frac{1}{z ( 1 - z ) ^{3}}

(e^{5 x} + 4 e^{- 3 x})^{2}

What is expand (-2x^2+8)/((x^2+4)^2) ?
The solution to expand (-2x^2+8)/((x^2+4)^2) is (-2x^2+8)/(x^4+8x^2+16)