What is expand (2s-4)/((s-1)(s^2+5x+6)) ?

The solution to expand (2s-4)/((s-1)(s^2+5x+6)) is (2s-4)/(s^3+5sx+6s-s^2-5x-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2s-4)/((s-1)(s^2+5x+6))

expand

\frac{2 s - 4}{( s - 1 ) ( s ^{2} + 5 x + 6 )}

\frac{2 s - 4}{s ^{3} + 5 s x + 6 s - s ^{2} - 5 x - 6}

Solution steps

\frac{2 s - 4}{( s - 1 ) ( s ^{2} + 5 x + 6 )}

Expand

(s - 1) (s^{2} + 5 x + 6) : s^{3} + 5 s x + 6 s - s^{2} - 5 x - 6

= \frac{2 s - 4}{s ^{3} + 5 s x + 6 s - s ^{2} - 5 x - 6}

\frac{8 + 4 s ^{2}}{s ^{s} ( s ^{2} - 4 )}

\frac{5 t ( 3 t ^{2} + 25 )}{8 ( t ^{2} + 5 ) ^{2}}

\frac{2}{( 2 x - k ) ^{2}}

\frac{( x d x )}{( x + 1 ) ^{8}}

\frac{d}{d t} ((x) (e^{t} (sin (t) + cos (t))))

What is expand (2s-4)/((s-1)(s^2+5x+6)) ?
The solution to expand (2s-4)/((s-1)(s^2+5x+6)) is (2s-4)/(s^3+5sx+6s-s^2-5x-6)