What is ((x-(pi/4))^2)/((tan(x)-1)^2) ?

The solution to ((x-(pi/4))^2)/((tan(x)-1)^2) is ((4x-pi)^2)/(16(tan(x)-1)^2)

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simplify ((x-(pi/4))^2)/((tan(x)-1)^2)

simplify

\frac{( x - ( \frac{π}{4} ) ) ^{2}}{( tan ( x ) - 1 ) ^{2}}

\frac{( 4 x - π ) ^{2}}{16 ( tan ( x ) - 1 ) ^{2}}

Solution steps

\frac{( x - ( \frac{π}{4} ) ) ^{2}}{( tan ( x ) - 1 ) ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{( x - \frac{π}{4} ) ^{2}}{( tan ( x ) - 1 ) ^{2}} = (\frac{x - \frac{π}{4}}{tan ( x ) - 1})^{2}

= (\frac{x - \frac{π}{4}}{tan ( x ) - 1})^{2}

\frac{x - \frac{π}{4}}{tan ( x ) - 1} = \frac{4 x - π}{4 ( tan ( x ) - 1 )}

= (\frac{x \cdot 4 - π}{4 ( tan ( x ) - 1 )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 4 x - π ) ^{2}}{( 4 ( tan ( x ) - 1 ) ) ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(4 (tan (x) - 1))^{2} = 4^{2} (tan (x) - 1)^{2}

= \frac{( 4 x - π ) ^{2}}{4 ^{2} ( tan ( x ) - 1 ) ^{2}}

4^{2} = 16

= \frac{( 4 x - π ) ^{2}}{16 ( tan ( x ) - 1 ) ^{2}}

e^{x} e^{3 x}

- 3 x^{4} y (6 x^{3} y^{5})

(sec^{2} (x))^{\frac{3}{2}}

f^{- 1} (22)

What is ((x-(pi/4))^2)/((tan(x)-1)^2) ?
The solution to ((x-(pi/4))^2)/((tan(x)-1)^2) is ((4x-pi)^2)/(16(tan(x)-1)^2)