What is e^{-at}sin(wt)u(t-1) ?

The solution to e^{-at}sin(wt)u(t-1) is (usin(tw)(t-1))/(e^{at)}

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simplify e^{-at}sin(wt)u(t-1)

simplify

e^{- a t} sin (wt) u (t - 1)

\frac{u sin ( tw ) ( t - 1 )}{e ^{a t}}

Solution steps

e^{- a t} sin (wt) u (t - 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{a t}} u sin (tw) (t - 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( wt ) u ( t - 1 )}{e ^{a t}}

Multiply:

1 \cdot sin (wt) = sin (wt)

= \frac{u sin ( tw ) ( t - 1 )}{e ^{a t}}

11.7 \cdot 1 0^{- 6}

(6.7 \cdot 1 0^{- 11}) (2 \cdot 1 0^{24}) (8 \cdot 1 0^{30})

30 (2)^{t} \cdot 8 (1.5)^{t}

(\frac{1}{2} a^{2} b) \cdot (\frac{2}{5} a b^{3})

What is e^{-at}sin(wt)u(t-1) ?
The solution to e^{-at}sin(wt)u(t-1) is (usin(tw)(t-1))/(e^{at)}