What is (2ab^2f^2)(4a^3b^2f^2) ?

The solution to (2ab^2f^2)(4a^3b^2f^2) is 8a^4b^4f^4

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simplify (2ab^2f^2)(4a^3b^2f^2)

simplify

(2 a b^{2} f^{2}) (4 a^{3} b^{2} f^{2})

8 a^{4} b^{4} f^{4}

Solution steps

(2 a b^{2} f^{2}) (4 a^{3} b^{2} f^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a a^{3} = a^{1 + 3}

= 2 b^{2} f^{2} \cdot 4 a^{1 + 3} b^{2} f^{2}

Add the numbers:

1 + 3 = 4

= 2 b^{2} f^{2} \cdot 4 a^{4} b^{2} f^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b^{2} b^{2} = b^{2 + 2}

= 2 f^{2} \cdot 4 a^{4} b^{2 + 2} f^{2}

Add the numbers:

2 + 2 = 4

= 2 f^{2} \cdot 4 a^{4} b^{4} f^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

f^{2} f^{2} = f^{2 + 2}

= 2 \cdot 4 a^{4} b^{4} f^{2 + 2}

Add the numbers:

2 + 2 = 4

= 2 \cdot 4 a^{4} b^{4} f^{4}

Multiply the numbers:

2 \cdot 4 = 8

= 8 a^{4} b^{4} f^{4}

(30 (2)^{t}) \cdot (8 (1.5)^{t})

2.6 \cdot 1 0^{- 4}

4.8456 e^{- 0.2019}

(e^{\frac{- x}{2}})^{2}

x^{2} (x - 4)^{2}

What is (2ab^2f^2)(4a^3b^2f^2) ?
The solution to (2ab^2f^2)(4a^3b^2f^2) is 8a^4b^4f^4