What is 3x^2y^2(2x^4y^2-3x^2y-1) ?

The solution to 3x^2y^2(2x^4y^2-3x^2y-1) is 3x^2y^2(2x^4y^2-3x^2y-1)

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simplify 3x^2y^2(2x^4y^2-3x^2y-1)

simplify

3 x^{2} y^{2} (2 x^{4} y^{2} - 3 x^{2} y - 1)

3 x^{2} y^{2} (2 x^{4} y^{2} - 3 x^{2} y - 1)

Solution steps

3 x^{2} y^{2} (2 x^{4} y^{2} - 3 x^{2} y - 1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} y^{2} = (x y)^{2}

= 3 (x y)^{2} (2 x^{4} y^{2} - 3 x^{2} y - 1)

(x y)^{2} = x^{2} y^{2}

= 3 x^{2} y^{2} (2 x^{4} y^{2} - 3 x^{2} y - 1)

e^{- 0.2136}

3 (- 2) e^{- 2}

6 \cdot e^{- 0.087 \cdot 20}

(b^{3} c^{2} d^{2}) (b^{2} c^{4} d^{6})

8.5 \cdot 1 0^{- 3}

What is 3x^2y^2(2x^4y^2-3x^2y-1) ?
The solution to 3x^2y^2(2x^4y^2-3x^2y-1) is 3x^2y^2(2x^4y^2-3x^2y-1)