What are the solutions to the equation 6x^2+9x-1=0 ?

The solutions to the equation 6x^2+9x-1=0 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)

Find the zeros of 6x^2+9x-1=0

The zeros of 6x^2+9x-1=0 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)

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6 x^{2} + 9 x - 1 = 0

x = \frac{- 9 + 105}{12}, x = \frac{- 9 - 105}{12}

Decimal Notation

x = 0.10391 \dots, x = - 1.60391 \dots

Solution steps

6 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 1) = 105

x_{1, 2} = \frac{- 9 \pm 105}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 105}{2 \cdot 6}, x_{2} = \frac{- 9 - 105}{2 \cdot 6}

x = \frac{- 9 + 105}{2 \cdot 6} : \frac{- 9 + 105}{12}

x = \frac{- 9 - 105}{2 \cdot 6} : \frac{- 9 - 105}{12}

The solutions to the quadratic equation are:

x = \frac{- 9 + 105}{12}, x = \frac{- 9 - 105}{12}

\frac{π}{32} (40)^{4}

2 x^{2} - 8 = 31 x - 2 x^{2}

3 x^{2} + 16 x - 12 < 0

z^{2} + 3 z - 40 = 0

x^{2} - 9 = - 15

What are the solutions to the equation 6x^2+9x-1=0 ?
The solutions to the equation 6x^2+9x-1=0 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)
Find the zeros of 6x^2+9x-1=0
The zeros of 6x^2+9x-1=0 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)