What is [(x^{-4})^{1/5}]^{1/6} ?

The solution to [(x^{-4})^{1/5}]^{1/6} is 1/(x^{2/15)}

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simplify [(x^{-4})^{1/5}]^{1/6}

simplify

[(x^{- 4})^{\frac{1}{5}}]^{\frac{1}{6}}

\frac{1}{x ^{\frac{2}{15}}}

Solution steps

[(x^{- 4})^{\frac{1}{5}}]^{\frac{1}{6}}

(x^{- 4})^{\frac{1}{5}} : x^{- \frac{4}{5}}

= [x^{- \frac{4}{5}}]^{\frac{1}{6}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= x^{(- \frac{4}{5}) \frac{1}{6}}

(- \frac{4}{5}) \frac{1}{6} = - \frac{2}{15}

= x^{- \frac{2}{15}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{x ^{\frac{2}{15}}}

2000000 (1 + 0.03)^{- 24}

(x^{2} + a)^{2} (x^{2} - a)^{2}

2 (6.67 \cdot 1 0^{- 11}) (1.99 \cdot 1 0^{30})

\frac{2 a}{3} \cdot \frac{3}{2 a}

3 x^{2} (x + 1)^{2}

What is [(x^{-4})^{1/5}]^{1/6} ?
The solution to [(x^{-4})^{1/5}]^{1/6} is 1/(x^{2/15)}