What are the solutions to the equation r^2-8r+10=0 ?

The solutions to the equation r^2-8r+10=0 are r=4+sqrt(6),r=4-sqrt(6)

Find the zeros of r^2-8r+10=0

The zeros of r^2-8r+10=0 are r=4+sqrt(6),r=4-sqrt(6)

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r^{2} - 8 r + 10 = 0

r = 4 + 6, r = 4 - 6

Decimal Notation

r = 6.44948 \dots, r = 1.55051 \dots

Solution steps

r^{2} - 8 r + 10 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 10 = 26

r_{1, 2} = \frac{- ( - 8 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 6}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 6}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 6}{2 \cdot 1} : 4 + 6

r = \frac{- ( - 8 ) - 2 6}{2 \cdot 1} : 4 - 6

The solutions to the quadratic equation are:

r = 4 + 6, r = 4 - 6

lo g_{\frac{1}{3}} (2 \cdot (- 10)^{2} + 10 + 3) + 2 = 0

2 \cdot (10 - z) + 10 - z + z + 13 + 10 - z = 88

\frac{1}{3} (b - 4) = 1

4 a^{2} - 12 a - (a - 3) = 0

20 = x^{2}

What are the solutions to the equation r^2-8r+10=0 ?
The solutions to the equation r^2-8r+10=0 are r=4+sqrt(6),r=4-sqrt(6)
Find the zeros of r^2-8r+10=0
The zeros of r^2-8r+10=0 are r=4+sqrt(6),r=4-sqrt(6)