What is sqrt(2x)\sqrt[3]{6x}\sqrt[6]{5/(3x)} ?

The solution to sqrt(2x)\sqrt[3]{6x}\sqrt[6]{5/(3x)} is 2^{5/6}\sqrt[3]{3}\sqrt[6]{5/(3x)}x^{5/6}

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simplify sqrt(2x)\sqrt[3]{6x}\sqrt[6]{5/(3x)}

simplify

Solution steps

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

2 x = 2 x

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

Factor integer

6 = 2 \cdot 3

Apply radical rule:

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{1}{2} + \frac{1}{3}} = 2^{\frac{5}{6}}

x^{\frac{1}{2} + \frac{1}{3}} = x^{\frac{5}{6}}

(9 x^{2}) (4 x^{2})

\frac{1}{0.86} \cdot e^{- (\frac{1}{0.86} + 1)}

(e^{\frac{- x}{a}})^{2}

\frac{e ^{5 x}}{e ^{x}}

\frac{x - 7}{x + 7}

What is sqrt(2x)\sqrt[3]{6x}\sqrt[6]{5/(3x)} ?
The solution to sqrt(2x)\sqrt[3]{6x}\sqrt[6]{5/(3x)} is 2^{5/6}\sqrt[3]{3}\sqrt[6]{5/(3x)}x^{5/6}