What is 1.02(log_{10}(1228000))^{-2.5} ?

The solution to 1.02(log_{10}(1228000))^{-2.5} is (51)/(50log_{10)(1228000)^{2.5}}

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simplify 1.02(log_{10}(1228000))^{-2.5}

simplify

1.02 (lo g_{10} (1228000))^{- 2.5}

\frac{51}{50 lo g _{10} ( 1228000 ) ^{2.5}}

Decimal Notation

0.01114 \dots

Solution steps

1.02 lo g_{10} (1228000)^{- 2.5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

lo g_{10} (1228000)^{- 2.5} = \frac{1}{lo g _{10} ( 1228000 ) ^{2.5}}

= 1.02 \cdot \frac{1}{lo g _{10} ( 1228000 ) ^{2.5}}

1.02 \cdot \frac{1}{lo g _{10} ( 1228000 ) ^{2.5}} = \frac{1.02}{lo g _{10} ( 1228000 ) ^{2.5}}

= \frac{1.02}{lo g _{10} ( 1228000 ) ^{2.5}}

\frac{1.02}{lo g _{10} ( 1228000 ) ^{2.5}} = \frac{102}{100 lo g _{10} ( 1228000 ) ^{2.5}}

= \frac{102}{100 lo g _{10} ( 1228000 ) ^{2.5}}

Factor the number:

102 = 2 \cdot 51

= \frac{2 \cdot 51}{100 lo g _{10} ( 1228000 ) ^{2.5}}

Factor the number:

100 = 2 \cdot 50

= \frac{2 \cdot 51}{2 \cdot 50 lo g _{10} ( 1228000 ) ^{2.5}}

Cancel the common factor:

2

= \frac{51}{50 lo g _{10} ( 1228000 ) ^{2.5}}

(x + 4)^{2} (x - 5)^{2}

(2 x + 3)^{2} (2 x - 3)^{2}

\frac{3}{2 w}

e^{- l n (x)}

\frac{( - 2 ) ^{n}}{2 ^{n}}

What is 1.02(log_{10}(1228000))^{-2.5} ?
The solution to 1.02(log_{10}(1228000))^{-2.5} is (51)/(50log_{10)(1228000)^{2.5}}