What are the solutions to the equation 25=4x^2-5x-50 ?

The solutions to the equation 25=4x^2-5x-50 are x=5,x=-15/4

Find the zeros of 25=4x^2-5x-50

The zeros of 25=4x^2-5x-50 are x=5,x=-15/4

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25 = 4 x^{2} - 5 x - 50

x = 5, x = - \frac{15}{4}

Decimal Notation

x = 5, x = - 3.75

Solution steps

25 = 4 x^{2} - 5 x - 50

Switch sides

4 x^{2} - 5 x - 50 = 25

Move

25

to the left side

4 x^{2} - 5 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 75 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 75) = 35

x_{1, 2} = \frac{- ( - 5 ) \pm 35}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 35}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 35}{2 \cdot 4}

x = \frac{- ( - 5 ) + 35}{2 \cdot 4} : 5

x = \frac{- ( - 5 ) - 35}{2 \cdot 4} : - \frac{15}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{15}{4}

1 = \frac{1}{3} (4 v + 3)

6 - \frac{1}{6} x = \frac{16}{3}

5 x - \frac{2}{5} \leq 2 - \frac{7 x}{2} < 3

18 x^{2} y^{3} - 9 x^{2}

What are the solutions to the equation 25=4x^2-5x-50 ?
The solutions to the equation 25=4x^2-5x-50 are x=5,x=-15/4
Find the zeros of 25=4x^2-5x-50
The zeros of 25=4x^2-5x-50 are x=5,x=-15/4