What is (x-8)^2(x-4)^2(x+1)^2 ?

The solution to (x-8)^2(x-4)^2(x+1)^2 is (x-8)^2(x-4)^2(x+1)^2

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simplify (x-8)^2(x-4)^2(x+1)^2

simplify

(x - 8)^{2} (x - 4)^{2} (x + 1)^{2}

(x - 8)^{2} (x - 4)^{2} (x + 1)^{2}

Solution steps

(x - 8)^{2} (x - 4)^{2} (x + 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x - 8)^{2} (x - 4)^{2} (x + 1)^{2} = ((x - 8) (x - 4) (x + 1))^{2}

= ((x - 8) (x - 4) (x + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x - 8)^{2} (x - 4)^{2} (x + 1)^{2}

- 2 e^{- x} (e^{- x})

(x^{2} - 4)^{2} (x + 1)^{2}

{[(2 x^{2})^{3}]^{- 4}}^{- 1}

(e^{- \frac{1}{2}})^{2}

(1.007 \cdot 1 0^{- 12}) (1400)

What is (x-8)^2(x-4)^2(x+1)^2 ?
The solution to (x-8)^2(x-4)^2(x+1)^2 is (x-8)^2(x-4)^2(x+1)^2