What is e^{(-6t)}u(4e^5t-cos(2t)) ?

The solution to e^{(-6t)}u(4e^5t-cos(2t)) is (u(4e^5t-cos(2t)))/(e^{6t)}

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simplify e^{(-6t)}u(4e^5t-cos(2t))

simplify

e^{(- 6 t)} u (4 e^{5} t - cos (2 t))

\frac{u ( 4 e ^{5} t - cos ( 2 t ) )}{e ^{6 t}}

Solution steps

e^{(- 6 t)} u (4 e^{5} t - cos (2 t))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{6 t}} u (4 e^{5} t - cos (2 t))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ( 4 e ^{5} t - cos ( 2 t ) )}{e ^{6 t}}

Multiply:

1 \cdot u = u

= \frac{u ( 4 e ^{5} t - cos ( 2 t ) )}{e ^{6 t}}

4.25 \cdot 1 0^{- 3}

3 x \cdot 4 x

e^{- \frac{s ^{2}}{2}} \cdot \frac{1}{s ^{2}}

\frac{e ^{- 4}}{e ^{- 2}}

(2.8 \cdot 1 0^{- 4}) (16)^{1.08}

What is e^{(-6t)}u(4e^5t-cos(2t)) ?
The solution to e^{(-6t)}u(4e^5t-cos(2t)) is (u(4e^5t-cos(2t)))/(e^{6t)}