What is 0.5a^2(1+ax)^{-3/2} ?

The solution to 0.5a^2(1+ax)^{-3/2} is (0.5a^2)/((1+ax)^{3/2)}

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simplify 0.5a^2(1+ax)^{-3/2}

simplify

0.5 a^{2} (1 + a x)^{- \frac{3}{2}}

\frac{0.5 a ^{2}}{( 1 + a x ) ^{\frac{3}{2}}}

Solution steps

0.5 a^{2} (1 + a x)^{- \frac{3}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(1 + a x)^{- \frac{3}{2}} = \frac{1}{( 1 + a x ) ^{\frac{3}{2}}}

= 0.5 a^{2} \frac{1}{( 1 + a x ) ^{\frac{3}{2}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{0.5 a ^{2} \cdot 1}{( 1 + a x ) ^{\frac{3}{2}}}

Multiply the numbers:

0.5 \cdot 1 = 0.5

= \frac{0.5 a ^{2}}{( 1 + a x ) ^{\frac{3}{2}}}

(\frac{7}{4} a^{6} b^{8} c^{2}) (\frac{2}{3} a^{2} b^{5} c)

e^{- 0.119}

2 e^{t} e^{- t}

(\frac{1}{4})^{\frac{1}{2}} \cdot (0.1)^{- 2}

What is 0.5a^2(1+ax)^{-3/2} ?
The solution to 0.5a^2(1+ax)^{-3/2} is (0.5a^2)/((1+ax)^{3/2)}