What is (80e^{-0.02x})x ?

The solution to (80e^{-0.02x})x is (80x)/(e^{0.02x)}

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simplify (80e^{-0.02x})x

simplify

(80 e^{- 0.02 x}) x

\frac{80 x}{e ^{0.02 x}}

Solution steps

(80 e^{- 0.02 x}) x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 80 \cdot \frac{1}{e ^{0.02 x}} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 80 x}{e ^{0.02 x}}

Multiply the numbers:

1 \cdot 80 = 80

= \frac{80 x}{e ^{0.02 x}}

(4 - x^{3})^{3}

(\frac{3}{5})^{4} (\frac{8}{5})^{- 12} (\frac{32}{5})^{6}

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(3.016 \cdot 1 0^{2}) \cdot (0.041 \cdot 1 0^{- 1})

\frac{d ^{2}}{d ^{2} t} (A e^{- (B x + Ct)^{2}})