What is (t-1)^{10}*U(t-1)*e^{-t+3} ?

The solution to (t-1)^{10}*U(t-1)*e^{-t+3} is e^{-t+3}U(t-1)^{11}

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simplify (t-1)^{10}U(t-1)e^{-t+3}

simplify

(t - 1)^{10} \cdot U (t - 1) \cdot e^{- t + 3}

e^{- t + 3} U (t - 1)^{11}

Solution steps

(t - 1)^{10} U (t - 1) e^{- t + 3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(t - 1)^{10} (t - 1) = (t - 1)^{10 + 1}

= U (t - 1)^{10 + 1} e^{- t + 3}

Add the numbers:

10 + 1 = 11

= U (t - 1)^{11} e^{- t + 3}

(8 x) (7 x^{2})

9.3 \cdot 1 0^{- 3}

2 \cdot e^{x} \cdot e^{- x}

3583 e^{- e^{- 0.02 (t - 66)}}

\frac{7}{22}

What is (t-1)^{10}*U(t-1)*e^{-t+3} ?
The solution to (t-1)^{10}*U(t-1)*e^{-t+3} is e^{-t+3}U(t-1)^{11}