What is the answer to 2+3(z-3)=z+3z+6z ?

The answer to 2+3(z-3)=z+3z+6z is z=-1

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2+3(z-3)=z+3z+6z

2 + 3 (z - 3) = z + 3 z + 6 z

z = - 1

Solution steps

2 + 3 (z - 3) = z + 3 z + 6 z

Add similar elements:

z + 3 z + 6 z = 10 z

2 + 3 (z - 3) = 10 z

Expand

2 + 3 (z - 3) : 3 z - 7

3 z - 7 = 10 z

Move

7

to the right side

3 z = 10 z + 7

Move

10 z

to the left side

- 7 z = 7

Divide both sides by

- 7

z = - 1

6 a + 9 = 55.1

\frac{2}{9} + \frac{1}{2}

13 \cdot 3

x^{2} + 5 x + 7 x + 35

h^{3} + 4 h^{2} - 25 h - 100