What is (4x)(3x+10)(2x)(x+20) ?

The solution to (4x)(3x+10)(2x)(x+20) is 4*2x^{2\circ}(x+20)(3x+10)

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simplify (4x)(3x+10)(2x)(x+20)

simplify

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

4^{\circ} \cdot 2^{\circ} x^{2 \circ} (x + 20)^{\circ} (3 x + 10)^{\circ}

Solution steps

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(4 x)^{\circ} = 4^{\circ} x^{\circ}

= 4^{\circ} x^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x)^{\circ} = 2^{\circ} x^{\circ}

= 4^{\circ} \cdot 2^{\circ} x^{\circ} x^{\circ} (3 x + 10)^{\circ} (x + 20)^{\circ}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{\circ} x^{\circ} = x^{\circ +\circ}

= 4^{\circ} (3 x + 10)^{\circ} \cdot 2^{\circ} x^{\circ +\circ} (x + 20)^{\circ}

Add similar elements:

\circ + \circ = 2 \circ

= 4^{\circ} (3 x + 10)^{\circ} \cdot 2^{\circ} x^{2 \circ} (x + 20)^{\circ}

4 e^{- 2 \cdot 4}

6.421 \cdot 1 0^{- 5} (\frac{1}{0.3048})^{2}

20 \cdot e^{- 0.8 (1)}

(2 x + 1)^{2} (2 x - 1)^{2}

\frac{e ^{8 x}}{e ^{5 x}}

What is (4x)(3x+10)(2x)(x+20) ?
The solution to (4x)(3x+10)(2x)(x+20) is 4*2x^{2\circ}(x+20)(3x+10)