What is x^4>=-1\land-4x-4<=-3 ?

The solution to x^4>=-1\land-4x-4 =-1/4

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x^4>=-1\land-4x-4<=-3

x^{4} \geq - 1 and - 4 x - 4 \leq - 3

x \geq - \frac{1}{4}

Interval Notation

[- \frac{1}{4}, \infty)

Decimal Notation

x \geq - 0.25

Solution steps

x^{4} \geq - 1 and - 4 x - 4 \leq - 3

x^{4} \geq - 1 :

True for all

x

- 4 x - 4 \leq - 3 : x \geq - \frac{1}{4}

Combine the intervals

True for all x and x \geq - \frac{1}{4}

Merge Overlapping Intervals

x \geq - \frac{1}{4}

\frac{x - 5}{x + 4} \leq 0

\frac{1}{3} - \frac{1}{9}

\frac{9 x + 12}{4} + \frac{3 x - 2}{2} = \frac{7}{2} x

x^{3} - 6 x^{2} + 9 x

\frac{12}{( 2 i ) ^{5}}

What is x^4>=-1\land-4x-4<=-3 ?
The solution to x^4>=-1\land-4x-4<=-3 is x>=-1/4