What is (8x^{2/3}y^{1/2})(3x^{1/6}y^{1/3}) ?

The solution to (8x^{2/3}y^{1/2})(3x^{1/6}y^{1/3}) is 24x^{5/6}y^{5/6}

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simplify (8x^{2/3}y^{1/2})(3x^{1/6}y^{1/3})

simplify

(8 x^{\frac{2}{3}} y^{\frac{1}{2}}) (3 x^{\frac{1}{6}} y^{\frac{1}{3}})

24 x^{\frac{5}{6}} y^{\frac{5}{6}}

Solution steps

(8 x^{\frac{2}{3}} y^{\frac{1}{2}}) (3 x^{\frac{1}{6}} y^{\frac{1}{3}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{\frac{2}{3}} x^{\frac{1}{6}} = x^{\frac{2}{3} + \frac{1}{6}}

= 8 y^{\frac{1}{2}} \cdot 3 x^{\frac{2}{3} + \frac{1}{6}} y^{\frac{1}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{\frac{1}{2}} y^{\frac{1}{3}} = y^{\frac{1}{2} + \frac{1}{3}}

= 8 \cdot 3 x^{\frac{2}{3} + \frac{1}{6}} y^{\frac{1}{2} + \frac{1}{3}}

x^{\frac{2}{3} + \frac{1}{6}} = x^{\frac{5}{6}}

= 8 \cdot 3 x^{\frac{5}{6}} y^{\frac{1}{2} + \frac{1}{3}}

y^{\frac{1}{2} + \frac{1}{3}} = y^{\frac{5}{6}}

= 8 \cdot 3 x^{\frac{5}{6}} y^{\frac{5}{6}}

Multiply the numbers:

8 \cdot 3 = 24

= 24 x^{\frac{5}{6}} y^{\frac{5}{6}}

e \cdot e^{6}

(e^{- 664.6976}) ((e^{0.3411})^{1971})

7 - 13 \cdot 7 + 13

1.2175 \cdot 1 0^{- 6}

x 2 x

What is (8x^{2/3}y^{1/2})(3x^{1/6}y^{1/3}) ?
The solution to (8x^{2/3}y^{1/2})(3x^{1/6}y^{1/3}) is 24x^{5/6}y^{5/6}