What is e^{-ln(4/5)= 5/25} ?

The solution to e^{-ln(4/5)= 5/25} is 1/(e^{5/25 ln(4/5)=)}

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simplify e^{-ln(4/5)= 5/25}

simplify

e^{- l n (\frac{4}{5}) = \frac{5}{25}}

\frac{1}{e ^{\frac{5}{25} l n (\frac{4}{5}) =}}

Solution steps

e^{- l n (\frac{4}{5}) = \frac{5}{25}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (\frac{4}{5}) = \frac{5}{25}}}

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What is e^{-ln(4/5)= 5/25} ?
The solution to e^{-ln(4/5)= 5/25} is 1/(e^{5/25 ln(4/5)=)}