What is e^{-2}(x^2+2y^2+4xy-2y-4x-1) ?

The solution to e^{-2}(x^2+2y^2+4xy-2y-4x-1) is 1/(e^2)(x^2+4xy-4x+2y^2-2y-1)

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simplify e^{-2}(x^2+2y^2+4xy-2y-4x-1)

simplify

e^{- 2} (x^{2} + 2 y^{2} + 4 x y - 2 y - 4 x - 1)

\frac{1}{e ^{2}} (x^{2} + 4 x y - 4 x + 2 y^{2} - 2 y - 1)

Solution steps

e^{- 2} (x^{2} + 2 y^{2} + 4 x y - 2 y - 4 x - 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2}} (x^{2} + 4 x y - 4 x + 2 y^{2} - 2 y - 1)

[(2^{2})^{2}]^{2}

[(- \frac{27}{8})^{- \frac{2}{3}}]^{\frac{1}{2}}

a - b a + b

e^{x} \cdot e^{\frac{1}{x}}

5.3 \cdot 1 0^{- 5}

What is e^{-2}(x^2+2y^2+4xy-2y-4x-1) ?
The solution to e^{-2}(x^2+2y^2+4xy-2y-4x-1) is 1/(e^2)(x^2+4xy-4x+2y^2-2y-1)