What is (4xyz)(2x^4y^4z^2) ?

The solution to (4xyz)(2x^4y^4z^2) is 8x^5y^5z^3

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simplify (4xyz)(2x^4y^4z^2)

simplify

(4 x yz) (2 x^{4} y^{4} z^{2})

8 x^{5} y^{5} z^{3}

Solution steps

(4 x yz) (2 x^{4} y^{4} z^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x x^{4} = x^{1 + 4}

= 4 yz \cdot 2 x^{1 + 4} y^{4} z^{2}

Add the numbers:

1 + 4 = 5

= 4 yz \cdot 2 x^{5} y^{4} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y y^{4} = y^{1 + 4}

= 4 z \cdot 2 x^{5} y^{1 + 4} z^{2}

Add the numbers:

1 + 4 = 5

= 4 z \cdot 2 x^{5} y^{5} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{2} = z^{1 + 2}

= 4 \cdot 2 x^{5} y^{5} z^{1 + 2}

Add the numbers:

1 + 2 = 3

= 4 \cdot 2 x^{5} y^{5} z^{3}

Multiply the numbers:

4 \cdot 2 = 8

= 8 x^{5} y^{5} z^{3}

7.1 \cdot 1 0^{- 4}

3^{2} \cdot π

(12 x^{3} y^{4} z^{5}) x (11 x^{2} y^{2} z^{2})

4.2 \cdot 1 0^{- 8}

4.2 \cdot 1 0^{- 6}