What are the solutions to the equation 3a^2-36=81 ?

The solutions to the equation 3a^2-36=81 are a=sqrt(39),a=-sqrt(39)

Find the zeros of 3a^2-36=81

The zeros of 3a^2-36=81 are a=sqrt(39),a=-sqrt(39)

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3 a^{2} - 36 = 81

a = 39, a = - 39

Decimal Notation

a = 6.24499 \dots, a = - 6.24499 \dots

Solution steps

3 a^{2} - 36 = 81

Move

36

to the right side

3 a^{2} = 117

Divide both sides by

3

a^{2} = 39

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 39, a = - 39

7 x + 1 = 9 x - 7

\frac{h ^{4}}{h ^{6}}

2 x^{2} - 13 x + 6 = 0

\frac{9 - x ^{2}}{x ^{2} - x - 2} \geq 0

e^{2 iπ}

What are the solutions to the equation 3a^2-36=81 ?
The solutions to the equation 3a^2-36=81 are a=sqrt(39),a=-sqrt(39)
Find the zeros of 3a^2-36=81
The zeros of 3a^2-36=81 are a=sqrt(39),a=-sqrt(39)