What is 10e^{-4t}cos(3t)u(t) ?

The solution to 10e^{-4t}cos(3t)u(t) is (10tucos(3t))/(e^{4t)}

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simplify 10e^{-4t}cos(3t)u(t)

simplify

10 e^{- 4 t} cos (3 t) u (t)

\frac{10 t u cos ( 3 t )}{e ^{4 t}}

Solution steps

10 e^{- 4 t} cos (3 t) u (t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 10 \cdot \frac{1}{e ^{4 t}} t u cos (3 t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 10 cos ( 3 t ) u t}{e ^{4 t}}

Multiply the numbers:

1 \cdot 10 = 10

= \frac{10 t u cos ( 3 t )}{e ^{4 t}}

2.19 \cdot 1 0^{- 4}

e^{- e^{0}}

(4 π \cdot 1 0^{- 7}) \cdot (600) \cdot (2.5)

e^{- 0.004}

(3 a^{2} b^{5} c) (6 a^{7} b^{4} c^{8})

What is 10e^{-4t}cos(3t)u(t) ?
The solution to 10e^{-4t}cos(3t)u(t) is (10tucos(3t))/(e^{4t)}