What are the solutions to the equation 49x^2-56x+16=0 ?

The solutions to the equation 49x^2-56x+16=0 are x= 4/7

Find the zeros of 49x^2-56x+16=0

The zeros of 49x^2-56x+16=0 are x= 4/7

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49 x^{2} - 56 x + 16 = 0

x = \frac{4}{7}

Solution steps

49 x^{2} - 56 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 49 \cdot 16}{2 \cdot 49}

(- 56)^{2} - 4 \cdot 49 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 56 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 56 )}{2 \cdot 49}

\frac{- ( - 56 )}{2 \cdot 49} = \frac{4}{7}

x = \frac{4}{7}

The solution to the quadratic equation is:

x = \frac{4}{7}

2 x + 1 = 3 x - 5

(2 x^{2} y)^{3} (3 x^{2} y^{3})

2 x^{2} + 3 x + 9 = 0

(\frac{w ^{- 2}}{3 v ^{\frac{1}{2}}})^{- 2}

x^{2} + 6 x + 3 = 2 x

What are the solutions to the equation 49x^2-56x+16=0 ?
The solutions to the equation 49x^2-56x+16=0 are x= 4/7
Find the zeros of 49x^2-56x+16=0
The zeros of 49x^2-56x+16=0 are x= 4/7