What is (z+1)^2(z^2-z+1)^2 ?

The solution to (z+1)^2(z^2-z+1)^2 is (z+1)^2(z^2-z+1)^2

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simplify (z+1)^2(z^2-z+1)^2

simplify

(z + 1)^{2} (z^{2} - z + 1)^{2}

(z + 1)^{2} (z^{2} - z + 1)^{2}

Solution steps

(z + 1)^{2} (z^{2} - z + 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(z + 1)^{2} (z^{2} - z + 1)^{2} = ((z + 1) (z^{2} - z + 1))^{2}

= ((z + 1) (z^{2} - z + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (z + 1)^{2} (z^{2} - z + 1)^{2}

1.4 \cdot 1 0^{- 1}

e^{- 2 l n ∣ x + 1 ∣}

e^{- u^{2}}

(23 \cdot 1 0^{- 2})^{3} \cdot 30 \cdot 1 0^{- 2} \cdot 9.8

(x - 1)^{2} \cdot (x + 2)^{2}

What is (z+1)^2(z^2-z+1)^2 ?
The solution to (z+1)^2(z^2-z+1)^2 is (z+1)^2(z^2-z+1)^2