What are the solutions to the equation 1/4 a^2+4=2a ?

The solutions to the equation 1/4 a^2+4=2a are a=4

Find the zeros of 1/4 a^2+4=2a

The zeros of 1/4 a^2+4=2a are a=4

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\frac{1}{4} a^{2} + 4 = 2 a

a = 4

Solution steps

\frac{1}{4} a^{2} + 4 = 2 a

Multiply both sides by

4

a^{2} + 16 = 8 a

Move

8 a

to the left side

a^{2} + 16 - 8 a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 8 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

a_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

a = 4

The solution to the quadratic equation is:

a = 4

(27)^{\frac{2}{3}}

a^{2} + 13 a + 36

\frac{3}{2} r + 2 = 8 - \frac{3}{2} r

x^{2} + 10 x + 16 = 0

- 6 y + 13 + 9 y = 8 y - 3

What are the solutions to the equation 1/4 a^2+4=2a ?
The solutions to the equation 1/4 a^2+4=2a are a=4
Find the zeros of 1/4 a^2+4=2a
The zeros of 1/4 a^2+4=2a are a=4