What is (sqrt((4x^2+4x+2)'))^2 ?

The solution to (sqrt((4x^2+4x+2)'))^2 is (4x^2+4x+2)'

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simplify (sqrt((4x^2+4x+2)'))^2

simplify

((4 x^{2} + 4 x + 2)^{'})^{2}

(4 x^{2} + 4 x + 2)'

Solution steps

((4 x^{2} + 4 x + 2)^{'})^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (((4 x^{2} + 4 x + 2)^{^{'}})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= ((4 x^{2} + 4 x + 2)^{^{'}})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

= (4 x^{2} + 4 x + 2)^{'}

e^{- \frac{16}{450}}

(\frac{1}{4} x) (\frac{1}{3} x^{3})

e^{- (0.1)^{2}}

e^{- 2} \cdot e^{6}

e^{- r t} (\frac{k e ^{r t}}{r} + C)

What is (sqrt((4x^2+4x+2)'))^2 ?
The solution to (sqrt((4x^2+4x+2)'))^2 is (4x^2+4x+2)'