What is (x^e+1)^2(x^e-1)^2(x^e+1)^2 ?

The solution to (x^e+1)^2(x^e-1)^2(x^e+1)^2 is (x^e+1)^4(x^e-1)^2

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simplify (x^e+1)^2(x^e-1)^2(x^e+1)^2

simplify

(x^{e} + 1)^{2} (x^{e} - 1)^{2} (x^{e} + 1)^{2}

(x^{e} + 1)^{4} (x^{e} - 1)^{2}

Solution steps

(x^{e} + 1)^{2} (x^{e} - 1)^{2} (x^{e} + 1)^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(x^{e} + 1)^{2} (x^{e} + 1)^{2} = (x^{e} + 1)^{2 + 2}

= (x^{e} - 1)^{2} (x^{e} + 1)^{2 + 2}

Add the numbers:

2 + 2 = 4

= (x^{e} - 1)^{2} (x^{e} + 1)^{4}

e^{- 0.01 x y^{2}}

10 e^{- 2 \cdot 2}

\frac{13}{41}

e^{(- \frac{1}{2} \cdot l n (1 + x^{2}))}

What is (x^e+1)^2(x^e-1)^2(x^e+1)^2 ?
The solution to (x^e+1)^2(x^e-1)^2(x^e+1)^2 is (x^e+1)^4(x^e-1)^2