What are the solutions to the equation x^2+25=49 ?

The solutions to the equation x^2+25=49 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of x^2+25=49

The zeros of x^2+25=49 are x=2sqrt(6),x=-2sqrt(6)

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x^{2} + 25 = 49

x = 26, x = - 26

Solution steps

x^{2} + 25 = 49

Move

25

to the right side

x^{2} = 24

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 24, x = - 24

24 = 26

- 24 = - 26

x = 26, x = - 26

3 x^{2} + 27 x + 54

\frac{h}{3} + 7 = 4

\frac{( x ^{2} - 16 )}{x ^{4} - 16} < 0

4 x = - 24

x^{3} + 10 x^{2} + 22 x + 12

What are the solutions to the equation x^2+25=49 ?
The solutions to the equation x^2+25=49 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of x^2+25=49
The zeros of x^2+25=49 are x=2sqrt(6),x=-2sqrt(6)