What is (R^2+4)^2(R^2-4)^2 ?

The solution to (R^2+4)^2(R^2-4)^2 is (R^2+4)^2(R^2-4)^2

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simplify (R^2+4)^2(R^2-4)^2

simplify

(R^{2} + 4)^{2} (R^{2} - 4)^{2}

(R^{2} + 4)^{2} (R^{2} - 4)^{2}

Solution steps

(R^{2} + 4)^{2} (R^{2} - 4)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(R^{2} + 4)^{2} (R^{2} - 4)^{2} = ((R^{2} + 4) (R^{2} - 4))^{2}

= ((R^{2} + 4) (R^{2} - 4))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (R^{2} + 4)^{2} (R^{2} - 4)^{2}

(4 x y^{3}) (3 x^{3} y^{5}) (9 x^{4} y)

e^{- x l n (c)}

\frac{e ^{- j w}}{e ^{- j \frac{w}{2}}}

18.5 \cdot e^{- 5}

What is (R^2+4)^2(R^2-4)^2 ?
The solution to (R^2+4)^2(R^2-4)^2 is (R^2+4)^2(R^2-4)^2