What is \sqrt[3]{(2x^2-x-3)^2} ?

The solution to \sqrt[3]{(2x^2-x-3)^2} is (2x^2-x-3)^{2/3}

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simplify \sqrt[3]{(2x^2-x-3)^2}

simplify

(2 x^{2} - x - 3)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((2 x^{2} - x - 3)^{2})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (2 x^{2} - x - 3)^{2 \cdot \frac{1}{3}}

2 \cdot \frac{1}{3} = \frac{2}{3}

= (2 x^{2} - x - 3)^{\frac{2}{3}}

e^{3 x} e^{2}

(e^{(- 0.2)}) (sin (3 x - 0.59))

(200 (1.1)^{t}) (5000 (1.111)^{t})

e^{- 0.41}

, (\frac{2}{3})^{2} \cdot (\frac{3}{2})^{- 1} \cdot 2^{- 1} \cdot (\frac{1}{4})^{0}

What is \sqrt[3]{(2x^2-x-3)^2} ?
The solution to \sqrt[3]{(2x^2-x-3)^2} is (2x^2-x-3)^{2/3}