What is (xyz)(x^2y^3z^4)(xy^2z^3) ?

The solution to (xyz)(x^2y^3z^4)(xy^2z^3) is x^4y^6z^8

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simplify (xyz)(x^2y^3z^4)(xy^2z^3)

simplify

(x yz) (x^{2} y^{3} z^{4}) (x y^{2} z^{3})

x^{4} y^{6} z^{8}

Solution steps

(x yz) (x^{2} y^{3} z^{4}) (x y^{2} z^{3})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x x^{2} x = x^{1 + 2 + 1}

= yz y^{3} z^{4} x^{1 + 2 + 1} y^{2} z^{3}

Add the numbers:

1 + 2 + 1 = 4

= yz y^{3} z^{4} x^{4} y^{2} z^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y y^{3} y^{2} = y^{1 + 3 + 2}

= z z^{4} x^{4} y^{1 + 3 + 2} z^{3}

Add the numbers:

1 + 3 + 2 = 6

= z z^{4} x^{4} y^{6} z^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{4} z^{3} = z^{1 + 4 + 3}

= x^{4} y^{6} z^{1 + 4 + 3}

Add the numbers:

1 + 4 + 3 = 8

= x^{4} y^{6} z^{8}

- \frac{π}{2} \cdot e^{- 0.2 \cdot 4}

8.6 \cdot 1 0^{- 4}

\frac{( 9 ) ^{5}}{5 !} e^{- 9}

e^{4 x} \cdot e^{- 4 x}

- \frac{1}{3} e^{- 3 x} \cdot e^{x}

What is (xyz)(x^2y^3z^4)(xy^2z^3) ?
The solution to (xyz)(x^2y^3z^4)(xy^2z^3) is x^4y^6z^8