What is factor m^6-64 ?

The solution to factor m^6-64 is (m+2)(m-2)(m^2+4+2m)(m^2+4-2m)

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factor m^6-64

factor

m^{6} - 64

(m + 2) (m - 2) (m^{2} + 4 + 2 m) (m^{2} + 4 - 2 m)

Solution steps

m^{6} - 64

Apply exponent rules

= (m^{2})^{3} - 4^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(m^{2})^{3} - 4^{3} = (m^{2} - 4) (m^{4} + 4 m^{2} + 4^{2})

= (m^{2} - 4) (m^{4} + 4 m^{2} + 4^{2})

Factor

m^{2} - 4 : (m + 2) (m - 2)

= (m + 2) (m - 2) (m^{4} + 4 m^{2} + 4^{2})

Factor

m^{4} + 4 m^{2} + 4^{2} : (m^{2} + 4 + 2 m) (m^{2} + 4 - 2 m)

= (m + 2) (m - 2) (m^{2} + 4 + 2 m) (m^{2} + 4 - 2 m)

- 4 x + 12 \geq 20

(m - n)^{2} - 16

\frac{8}{7} ∣ x ∣ = 3

0 = s^{2} - 10 s + 34

10 + 3 (- 9 n + 1) > - 2 n - 2 + 4

What is factor m^6-64 ?
The solution to factor m^6-64 is (m+2)(m-2)(m^2+4+2m)(m^2+4-2m)