What is 7.84*10^{-7}*(1000^2-250^2)*0.4*160.17 ?

The solution to 7.84*10^{-7}*(1000^2-250^2)*0.4*160.17 is (1000^2*12.557328-784833)/(250000)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 7.8410^{-7}(1000^2-250^2)0.4160.17

simplify

7.84 \cdot 1 0^{- 7} \cdot (100 0^{2} - 25 0^{2}) \cdot 0.4 \cdot 160.17

\frac{100 0 ^{2} \cdot 12.557328 - 784833}{250000}

Decimal Notation

47.08998

Solution steps

7.84 \cdot 1 0^{- 7} (100 0^{2} - 25 0^{2}) \cdot 0.4 \cdot 160.17

Multiply the numbers:

7.84 \cdot 0.4 \cdot 160.17 = 502.29312

= 502.29312 \cdot 1 0^{- 7} (100 0^{2} - 25 0^{2})

= 1 0^{- 7} \cdot 502.29312 (100 0^{2} - 25 0^{2})

1 0^{- 7} = \frac{1}{10000000}

= \frac{1}{10000000} \cdot 502.29312 (100 0^{2} - 25 0^{2})

25 0^{2} = 62500

= \frac{1}{10000000} \cdot 502.29312 (100 0^{2} - 62500)

Expand

\frac{1}{10000000} \cdot 502.29312 (100 0^{2} - 62500) : \frac{100 0 ^{2} \cdot 12.557328 - 784833}{250000}

= \frac{100 0 ^{2} \cdot 12.557328 - 784833}{250000}

- 25 e^{- 0.2 (10)}

x^{2} (m x)

(3 q^{2} r^{2}) (3 q^{5} r^{3})

4.6 \cdot 1 0^{- 6}

(1.6 \cdot 1 0^{- 19}) \cdot 2

What is 7.84*10^{-7}*(1000^2-250^2)*0.4*160.17 ?
The solution to 7.84*10^{-7}*(1000^2-250^2)*0.4*160.17 is (1000^2*12.557328-784833)/(250000)