What is 4t^2(t-1)^2(t^2+1) ?

The solution to 4t^2(t-1)^2(t^2+1) is 4t^2(t-1)^2(t^2+1)

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simplify 4t^2(t-1)^2(t^2+1)

simplify

4 t^{2} (t - 1)^{2} (t^{2} + 1)

4 t^{2} (t - 1)^{2} (t^{2} + 1)

Solution steps

4 t^{2} (t - 1)^{2} (t^{2} + 1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

t^{2} (t - 1)^{2} = (t (t - 1))^{2}

= 4 (t (t - 1))^{2} (t^{2} + 1)

(t (t - 1))^{2} = t^{2} (t - 1)^{2}

= 4 t^{2} (t - 1)^{2} (t^{2} + 1)

(x - 6)^{2} (x - 12)^{2}

e^{- 28.553}

12 e^{- 0.01 (2)}

4.157 \cdot 1 0^{- 3}

2 x x (2 x)

What is 4t^2(t-1)^2(t^2+1) ?
The solution to 4t^2(t-1)^2(t^2+1) is 4t^2(t-1)^2(t^2+1)