What is (2yz)(2x^2yz^3) ?

The solution to (2yz)(2x^2yz^3) is 4y^2z^4x^2

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simplify (2yz)(2x^2yz^3)

simplify

(2 yz) (2 x^{2} y z^{3})

4 y^{2} z^{4} x^{2}

Solution steps

(2 yz) (2 x^{2} y z^{3})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= yz \cdot 2^{1 + 1} x^{2} y z^{3}

Add the numbers:

1 + 1 = 2

= yz \cdot 2^{2} x^{2} y z^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

yy = y^{1 + 1}

= z \cdot 2^{2} x^{2} y^{1 + 1} z^{3}

Add the numbers:

1 + 1 = 2

= z \cdot 2^{2} x^{2} y^{2} z^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{3} = z^{1 + 3}

= 2^{2} x^{2} y^{2} z^{1 + 3}

Add the numbers:

1 + 3 = 4

= 2^{2} x^{2} y^{2} z^{4}

2^{2} = 4

= 4 y^{2} z^{4} x^{2}

3.2 \cdot 1 0^{- 10}

\frac{2}{7} \cdot 7

3.2 \cdot 1 0^{- 16}

0.6 \cdot 1 0^{- 5}

(7.2 \cdot 1 0^{24}) (8.61 \cdot 1 0^{19})