What is (2x^2-xy+3y^2)*(x^2y^2) ?

The solution to (2x^2-xy+3y^2)*(x^2y^2) is x^2y^2(2x^2-xy+3y^2)

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simplify (2x^2-xy+3y^2)*(x^2y^2)

simplify

(2 x^{2} - x y + 3 y^{2}) \cdot (x^{2} y^{2})

x^{2} y^{2} (2 x^{2} - x y + 3 y^{2})

Solution steps

(2 x^{2} - x y + 3 y^{2}) (x^{2} y^{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} y^{2} = (x y)^{2}

= (2 x^{2} - x y + 3 y^{2}) (x y)^{2}

(x y)^{2} = x^{2} y^{2}

= x^{2} y^{2} (2 x^{2} - x y + 3 y^{2})

30 e^{- 0.3 (1)}

60 e^{- 0.0051 \cdot 135.9}

\frac{- 135}{27}

4.4 \cdot 1 0^{- 5}

30 e^{- 0.3 (2)}

What is (2x^2-xy+3y^2)*(x^2y^2) ?
The solution to (2x^2-xy+3y^2)*(x^2y^2) is x^2y^2(2x^2-xy+3y^2)