What is (\sqrt[3]{256a^4b^{12}})^{0.75} ?

The solution to (\sqrt[3]{256a^4b^{12}})^{0.75} is (256a^4b^{12})^{0.25}

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simplify (\sqrt[3]{256a^4b^{12}})^{0.75}

simplify

(256 a^{4} b^{12})^{0.25}

Solution steps

Apply radical rule:

= ((256 a^{4} b^{12})^{\frac{1}{3}})^{0.75}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (256 a^{4} b^{12})^{\frac{1}{3} \cdot 0.75}

\frac{1}{3} \cdot 0.75 = 0.25

= (256 a^{4} b^{12})^{0.25}

(x - 2)^{3} (x + 2)^{3}

t \cdot e^{- 4 t}

\frac{56}{81} (0.8)^{- \frac{10}{3}} (\frac{1}{4 !}) (1.2 - 1)^{4}

100 e^{- 0.2 (5)}

\frac{e ^{- x}}{e ^{- 4 x}}

What is (\sqrt[3]{256a^4b^{12}})^{0.75} ?
The solution to (\sqrt[3]{256a^4b^{12}})^{0.75} is (256a^4b^{12})^{0.25}