What is 10^{-15}*(e^{(0.7)/(26*10^{-3)}}-1) ?

The solution to 10^{-15}*(e^{(0.7)/(26*10^{-3)}}-1) is (e^{350/13}-1)/(10^{15)}

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simplify 10^{-15}(e^{(0.7)/(2610^{-3)}}-1)

simplify

1 0^{- 15} \cdot (e^{\frac{0.7}{26 \cdot 1 0 ^{- 3}}} - 1)

\frac{e ^{\frac{350}{13}} - 1}{1 0 ^{15}}

Decimal Notation

0.00049 \dots

Solution steps

1 0^{- 15} (e^{\frac{0.7}{26 \cdot 1 0 ^{- 3}}} - 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{1 0 ^{15}} (e^{\frac{0.7}{1 0 ^{- 3} \cdot 26}} - 1)

\frac{0.7}{26 \cdot 1 0 ^{- 3}} = \frac{350}{13}

= \frac{1}{1 0 ^{15}} (e^{\frac{350}{13}} - 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( e ^{\frac{350}{13}} - 1 )}{1 0 ^{15}}

1 \cdot (e^{\frac{350}{13}} - 1) = e^{\frac{350}{13}} - 1

= \frac{e ^{\frac{350}{13}} - 1}{1 0 ^{15}}

(v^{\circ})^{\frac{6}{7}} v^{\frac{11}{6}}

e^{- nk t} (e^{k t} - 1)^{n - m}

2 e^{2 t} \cdot 4 e^{2 t}

- 2 r e^{r^{2}} sin (θ) \cdot 2 r \cdot (- 2) sin (θ) \cdot e^{r^{2}}

What is 10^{-15}*(e^{(0.7)/(26*10^{-3)}}-1) ?
The solution to 10^{-15}*(e^{(0.7)/(26*10^{-3)}}-1) is (e^{350/13}-1)/(10^{15)}