What is \sqrt[3]{sqrt((2ba^3)(2a^2b^3))} ?

The solution to \sqrt[3]{sqrt((2ba^3)(2a^2b^3))} is cube root of 2}\sqrt[6]{b^4a^5

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simplify \sqrt[3]{sqrt((2ba^3)(2a^2b^3))}

simplify

Solution steps

Apply radical rule:

= (((2 b a^{3}) (2 a^{2} b^{3}))^{\frac{1}{2}})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= ((2 b a^{3}) (2 a^{2} b^{3}))^{\frac{1}{2} \cdot \frac{1}{3}}

\frac{1}{2} \cdot \frac{1}{3} = \frac{1}{6}

= ((2 b a^{3}) (2 a^{2} b^{3}))^{\frac{1}{6}}

Remove parentheses:

(a) = a

Simplify

2 b a^{3} \cdot 2 a^{2} b^{3} : 4 b^{4} a^{5}

Apply radical rule:

assuming

a \geq 0, b \geq 0

4 (m^{3} n)^{5}

(2.66 \cdot 1 0^{- 23}) (6.02214 \cdot 1 0^{23})

in t er sec (c) i o n es (x - 1)^{4}

(x - 1)^{2} e^{- x}

1.2 \cdot e^{- 0.98 x}

What is \sqrt[3]{sqrt((2ba^3)(2a^2b^3))} ?
The solution to \sqrt[3]{sqrt((2ba^3)(2a^2b^3))} is cube root of 2}\sqrt[6]{b^4a^5