What is ((e^{-5x}+e^y-1)/5)^{-1} ?

The solution to ((e^{-5x}+e^y-1)/5)^{-1} is 5/(e^y+e^{-5x)-1}

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simplify ((e^{-5x}+e^y-1)/5)^{-1}

simplify

(\frac{e ^{- 5 x} + e ^{y} - 1}{5})^{- 1}

\frac{5}{e ^{y} + e ^{- 5 x} - 1}

Solution steps

(\frac{e ^{- 5 x} + e ^{y} - 1}{5})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( \frac{e ^{- 5 x} + e ^{y} - 1}{5} )}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{5}{e ^{- 5 x} + e ^{y} - 1}

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What is ((e^{-5x}+e^y-1)/5)^{-1} ?
The solution to ((e^{-5x}+e^y-1)/5)^{-1} is 5/(e^y+e^{-5x)-1}