What is cos(2t)e^{-t(s+1)} ?

The solution to cos(2t)e^{-t(s+1)} is (cos(2t))/(e^{t(s+1))}

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simplify cos(2t)e^{-t(s+1)}

simplify

cos (2 t) e^{- t (s + 1)}

\frac{cos ( 2 t )}{e ^{t (s + 1)}}

Solution steps

cos (2 t) e^{- t (s + 1)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{t (s + 1)}} cos (2 t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( 2 t )}{e ^{t (s + 1)}}

Multiply:

1 \cdot cos (2 t) = cos (2 t)

= \frac{cos ( 2 t )}{e ^{t (s + 1)}}

(\frac{4}{3})^{2 x - 3}

\frac{4 ^{0}}{0 !} \cdot e^{- 4}

3 \cdot 1 0^{- 3} (\frac{7 π}{- 15})

60.656 e^{- 0.0892 (5)}

What is cos(2t)e^{-t(s+1)} ?
The solution to cos(2t)e^{-t(s+1)} is (cos(2t))/(e^{t(s+1))}