What are the solutions to the equation (10x+3)^2=3 ?

The solutions to the equation (10x+3)^2=3 are x=(sqrt(3)-3)/(10),x=(-sqrt(3)-3)/(10)

Find the zeros of (10x+3)^2=3

The zeros of (10x+3)^2=3 are x=(sqrt(3)-3)/(10),x=(-sqrt(3)-3)/(10)

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(10 x + 3)^{2} = 3

x = \frac{3 - 3}{10}, x = \frac{- 3 - 3}{10}

Solution steps

(10 x + 3)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

10 x + 3 = 3 : x = \frac{3 - 3}{10}

Solve

10 x + 3 = - 3 : x = \frac{- 3 - 3}{10}

The solutions to the quadratic equation are:

x = \frac{3 - 3}{10}, x = \frac{- 3 - 3}{10}

\frac{( x - 5 )}{x + 2} \geq - 6

(5 - 7)^{2}

\frac{x - 2}{8 x + 1} < 0

\frac{a - 2}{3} > a + 4

5 x^{2} - 5 x - 1 = 0

What are the solutions to the equation (10x+3)^2=3 ?
The solutions to the equation (10x+3)^2=3 are x=(sqrt(3)-3)/(10),x=(-sqrt(3)-3)/(10)
Find the zeros of (10x+3)^2=3
The zeros of (10x+3)^2=3 are x=(sqrt(3)-3)/(10),x=(-sqrt(3)-3)/(10)