What is 2x(4x^2)(2x^2+x+7) ?

The solution to 2x(4x^2)(2x^2+x+7) is 8x^3(2x^2+x+7)

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simplify 2x(4x^2)(2x^2+x+7)

simplify

2 x (4 x^{2}) (2 x^{2} + x + 7)

8 x^{3} (2 x^{2} + x + 7)

Solution steps

2 x (4 x^{2}) (2 x^{2} + x + 7)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x x^{2} = x^{1 + 2}

= 2 \cdot 4 x^{1 + 2} (2 x^{2} + x + 7)

Add the numbers:

1 + 2 = 3

= 2 \cdot 4 x^{3} (2 x^{2} + x + 7)

Multiply the numbers:

2 \cdot 4 = 8

= 8 x^{3} (2 x^{2} + x + 7)

6^{- l o g_{6} (3^{2})}

\frac{10000}{0.05} (1.05)^{- 25} e^{- 0.06 (25)}

- 9 u (3 u^{8})

(3 \cdot 1 0^{6}) (3 \cdot 1 0^{8})

What is 2x(4x^2)(2x^2+x+7) ?
The solution to 2x(4x^2)(2x^2+x+7) is 8x^3(2x^2+x+7)